MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        

A body freely falling from a tower covers a distance of S=h/2 in the last second of it's motion.the height of tower is?

5 years ago

Answers : (3)

akash luckey aggara
33 Points
							

is the ans 10

5 years ago
shivang belwariar
35 Points
							

we have the formula - S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND . ]

so using the formula ------

 

h/2 = u + a/2(2t-1)

 

h/10 = 2t-1 { u=0 & a=10}

 

t = h+10/20

 

so, total time = h+10/20

now by formula = h=ut + 1/2at^2, (u=0 a=10)

 

h=h^2+100+20h/80

 

on solving - h = 58.28 metres.

 

plz like my answer

5 years ago
sharjil deshmukh
4 Points
							

can we use \

S = u + g( total time - 1 -1/2}|

to get total time n thn subtitiute it in same eqation we wil get total distance|

is this ans right ???????????? 2 prsn who commented above

5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details