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A body freely falling from a tower covers a distance of S=h/2 in the last second of it's motion.the height of tower is?
is the ans 10
we have the formula - S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND . ]
so using the formula ------
h/2 = u + a/2(2t-1)
h/10 = 2t-1 { u=0 & a=10}
t = h+10/20
so, total time = h+10/20
now by formula = h=ut + 1/2at^2, (u=0 a=10)
h=h^2+100+20h/80
on solving - h = 58.28 metres.
plz like my answer
can we use \
S = u + g( total time - 1 -1/2}|to get total time n thn subtitiute it in same eqation we wil get total distance|is this ans right ???????????? 2 prsn who commented above
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