MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        

Find the force on a particle of mass m placed at the centre of a semicircular wire of length L and mass M.

10 years ago

Answers : (1)

Puneet Mittal AskiitiansExpert-IITD
22 Points
							


Hi Sanchit,

The answer is :

let R be raidus of wire , then , ∏R = L --- (1)

element of length RdΦ at angle Φ from centre will exert a force dF = Gm(M/L)(RdΦ)/R2

Similar force will be exerted by a element at angle -Φ from the centre.

Thus net force on m will be : 2dFcosΦ

Thus Force F = ∫2dFcosΦ   where Φ varies from 0 to 90

Thus F = 2∫(Gm(M/L)dΦ/R)cosΦ

F = 2GmM/LR ∫cosΦ dΦ where Φ varies from 0 to 90

F = 2GmM/LR ( 1 - 0 )

 Thus force on particle due to wire will be F = 2GMm/LR = 2GMm∏/L2 ( from (1) )

Please feel free to ask as many questions you have.

Puneet

9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details