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Can nyone help me wid the soved example number 19 given in the kinematics chapter of h c verma
Given: Reaction time - 0.20s
initial velocity - 54km/h = 15m/s
acceleration - -6.0m/s^2
To find distance travelled when brakes r to be applied:?
Final velocity - v = u+at
= 15+6*0.2
= 16.2
s=v^2-u^2/2a
= 16.2*16.2-15*15/12
= 22m
If u understand plz approve my answer
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