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A particle A of mass 10/7 kg is moving in the positive direction of x.Its initial position is x=0 & initial velocity is 1m/s.The velocity at x=10 is?

Nitesh Modi , 13 Years ago
Grade 12
anser 9 Answers
Suraj Tripathi

the velocity at x = 0 will be 1m/s as you have not mentioned any acceleration...

Last Activity: 13 Years ago
dinesh sharma

without accn. this impossible to predict about velocity.

Last Activity: 13 Years ago
Gaurav
The answer is possible if the velocity will differentiate w.r.t time and hence we got tthe acceleration by using eqn. S=ut+1/2at×t
Last Activity: 8 Years ago
dinesh sharma
Well...we dont know the acceleration is constant or variable and this is the real problem.so its impossible to predict the motion.
Last Activity: 8 Years ago
Akhil Jaywant
Chutiye graph to de hutiye..... Graph bhii hotaa h is ques me......................................................
Last Activity: 8 Years ago
Basma
This question cannot be solved as it is not given whether it is uniform motion or non uniform motion or accelarated motion.the mass is not needed to find velocity.
Last Activity: 8 Years ago
Amarjit
If there is no acceleration in x direction then its velocity will remain throughout the motion, hence velocityvat x=10 will be 1m/s.
Last Activity: 8 Years ago
Mohit
This graph contains a graph which is a straight line ... Graph is in between power ( watt) and disp (m)The graphs starts from (0,2) and end on (10,4)By this find relation between power and displacement and integrate it by using formulae p = force × velocity And put force = mass and acc.And acc = v dv/dx and integrate it Thanks
Last Activity: 8 Years ago
Shubham Patil
Area under P-x graph
∫pdx=∫(m  d/dt)vdx
∫mv^2dv=[mv^3/3]:(limits 1 to v both sides)
=10/7×1/3(v^3-1)
From graph:area=1/2(2+4)×10=30
Therefore 10/3×1/3(v^3-1)=30
v=4m/s
Hope it helps!!!
Cheers!!!
By Shubham Patil
 
Last Activity: 7 Years ago
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