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A particle A of mass 10/7 kg is moving in the positive direction of x.Its initial position is x=0 & initial velocity is 1m/s.The velocity at x=10 is?

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8 years ago

```							the velocity at x = 0 will be 1m/s as you have not mentioned any acceleration...
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8 years ago
```							without accn. this impossible to predict about velocity.
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8 years ago
```							The answer is possible if the velocity will differentiate w.r.t time and hence we got tthe acceleration by using eqn.  S=ut+1/2at×t
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3 years ago
```							Well...we dont know the acceleration is constant or variable and this is the real problem.so its impossible to predict the motion.
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3 years ago
```							Chutiye graph to de hutiye..... Graph bhii hotaa h is ques me......................................................
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3 years ago
```							This question cannot be solved as it is not given whether it is uniform motion or non uniform motion or accelarated motion.the mass is not needed to find velocity.
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3 years ago
```							If there is no acceleration in x direction then its velocity will remain throughout the motion, hence velocityvat x=10 will be 1m/s.
```
3 years ago
```							This graph contains a graph which is a straight line ... Graph is in between power ( watt) and disp (m)The graphs starts from (0,2) and end on (10,4)By this find relation between power and displacement and integrate it by using formulae p = force × velocity And put force = mass and acc.And acc = v dv/dx and integrate it Thanks
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3 years ago
```							Area under P-x graph∫pdx=∫(m  d/dt)vdx∫mv^2dv=[mv^3/3]:(limits 1 to v both sides)=10/7×1/3(v^3-1)From graph:area=1/2(2+4)×10=30Therefore 10/3×1/3(v^3-1)=30v=4m/sHope it helps!!!Cheers!!!By Shubham Patil
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2 years ago
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