Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
two blocks A and B of mass m a and m b respectivly are kept in contact on a frictionless table .the experimenter pushes the block A from behind so that the blocks accelerate if the block A exerts a force F on the block B .what is the force exerted by the experimenter on A ? KINDLY SEND ME ANS FR THIS QUESTION WITH F.B.D two blocks A and B of mass ma and mb respectivly are kept in contact on a frictionless table .the experimenter pushes the block A from behind so that the blocks accelerate if the block A exerts a force F on the block B .what is the force exerted by the experimenter on A ? KINDLY SEND ME ANS FR THIS QUESTION WITH F.B.D
two blocks A and B of mass ma and mb respectivly are kept in contact on a frictionless table .the experimenter pushes the block A from behind so that the blocks accelerate if the block A exerts a force F on the block B .what is the force exerted by the experimenter on A ?
KINDLY SEND ME ANS FR THIS QUESTION WITH F.B.D
Force acting on B = FLet Fext be the force exerted by the personTherefore the acceleration of the system Fext=( Ma+Mb)A -------------1Acceleration is common for both the blocks.Now, the force on B by A = F= Mb * AA=F/Mb --------- 2 Sub 2 in 1 Fext =(Ma+Mb)F / Mb
let the force exerted by the person is Fp now the acceleration of the system isa=Fp/Ma+Mb -------------1now let the force applied by block A on block B is Ftherefore F=Mb×aa=F/Mb--------------2since, the acceleration of the whole system is same then by eqauting equation 1 and 2 we getF/Mb=Fp/Ma+MbFp=(Ma+Mb)×F/Mbit is also return as Fp=( Ma/Mb+1)×F
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -