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sir pls pls solve this quotion
Dear Rohan One thing should be noted here that length of the rope is constant. let the length between the wedge and lower pully is x2 and length between the block and upper pully is x1 +dx1/dt =v1 and -dx2/dt =v2 Now length of the rope is constant so x2+ (x22+l2)1/2 +x1 =coonstant where l is a vertical distance between two pully which is constant now differentiate and put +dx1/dt =v1 and -dx2/dt =v2 and sinθ =x2/(x22+l2)1/2 and rearrange you will get v1=v2(1+sinθ) Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best rohan. Regards, Askiitians Experts Badiuddin
Dear Rohan
One thing should be noted here that length of the rope is constant.
let the length between the wedge and lower pully is x2
and length between the block and upper pully is x1
+dx1/dt =v1
and -dx2/dt =v2
Now length of the rope is constant
so x2+ (x22+l2)1/2 +x1 =coonstant where l is a vertical distance between two pully which is constant
now differentiate and put +dx1/dt =v1
and sinθ =x2/(x22+l2)1/2
and rearrange you will get
v1=v2(1+sinθ)
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best rohan. Regards, Askiitians Experts Badiuddin
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