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sir pls pls solve this quotion
Dear Rohan
One thing should be noted here that length of the rope is constant.
let the length between the wedge and lower pully is x2
and length between the block and upper pully is x1
+dx1/dt =v1
and -dx2/dt =v2
Now length of the rope is constant
so x2+ (x22+l2)1/2 +x1 =coonstant where l is a vertical distance between two pully which is constant
now differentiate and put +dx1/dt =v1
and sinθ =x2/(x22+l2)1/2
and rearrange you will get
v1=v2(1+sinθ)
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