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The time taken by a body to slide down a rough 45 degrees inclined plane is twice that required to slide down a smooth 45 degrees inclined plane.the coefficent of friction between the object and rough plane is given by :
a. 1/3
b. 3/4
c. root 3/4
d. root 4/3
rply pls...
hi rohan bhatia
accelarion along the downward direction of wedge
a1=(mgsin45-μmgcos45)/m
=(1-μ)g/√2
let total time taken is t
s=0*t +.5(a1)t^2
when wedge is frictionles
then acceleration
a2=g/√2
s=0*t/2 +.5(a2)*(t/2)^2
equate both value of s
μ=3/4
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hey ans is 3/4
when you compare
let x be length of the wedge
X = 1/2 gsinθ t2 for smooth plane
X = 1/2 (gsinθ-μcosθ)4t2 foe rough plane
you will get ams 3/4
thank u very much sir for solving my problems.
q. a block of mass m is resting on a wedge of angle θ with what minimum acceleration a should the wedge move so that the mass m falls freely ?
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