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the upper half of an inclined plane with inclination fi is perfectly smooth ,while the lower half is rough .a body starting from rest at the top will again come to rest at the bottom if coefficient of friction for the lower half is

nivi jain , 13 Years ago
Grade 12
anser 2 Answers
hunaid
suppose length of plane is L.
when block descends the plane, rise in kinetic energy = fall in potential energy = mgLsinθ ---eq (1)
work done by friction is :  μ*(reaction)*distance
0  + μ(mgcosθ )*(L/2)  
=  μ(mgcosθ )*(L/2)  
[work done against friction for the upper half of plane is zero]
Now work done = change in KE
mgLsinθ =  μ(mgcosθ )*(L/2)
tanθ =  μ/2
μ = 2tanθ
Last Activity: 8 Years ago
Kushagra Madhukar
Dear student,
Please find the answer to your question.
 
Suppose length of plane is L.
when block descends the plane, rise in kinetic energy = fall in potential energy = mgLsinθ ---eq (1)
work done by friction =  μ(mgcosθ )*(L/2)
Now work done = change in KE
mgLsinθ =  μ(mgcosθ )*(L/2)
tanθ =  μ/2
μ = 2tanθ
 
Thanks and regards,
Kushagra
Last Activity: 5 Years ago
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