# a ship is travelling due east at 10 km/h. another ship heading 30degree east of north is always due north from the first ship.  the speed of second ship in km/h is

Sanjeev Malik IIT BHU
101 Points
11 years ago

always solve by leting two components as v1 in north nad v2(in east....as net b/w north n east).

as original speed at 30deg east of north so, so perpendiculat to it zero velocity.

v1sin30= v2sin60                 .........................1

also by relative concept as relative to other ship dirn is north so zero vel along east west direction...it gives

v2=10

thus find the ans...

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DEVANSH
13 Points
5 years ago

two components is v1 in north nad v2(in east....as net b/w north n east).

as original speed at 30deg east of north so, so perpendiculat to it zero velocity.

v1sin30= v2sin60                 .........................1

also by relative concept as relative to other ship dirn is north so zero vel along east west direction...it gives

v2=10

then x=10/sin(30º)=10/1/2=20 km/h