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a ship is travelling due east at 10 km/h. another ship heading 30degree east of north is always due north from the first ship. the speed of second ship in km/h is
always solve by leting two components as v1 in north nad v2(in east....as net b/w north n east).
as original speed at 30deg east of north so, so perpendiculat to it zero velocity.
v1sin30= v2sin60 .........................1
also by relative concept as relative to other ship dirn is north so zero vel along east west direction...it gives
v2=10
thus find the ans...
"like" the post below and click "yes" if it helps
two components is v1 in north nad v2(in east....as net b/w north n east).
then x=10/sin(30º)=10/1/2=20 km/h
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