MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        the relation between time t and positon x for a particle moving on x axis is given by t =p(x)square +qx find relation between velocity and acceleration??
10 years ago

Answers : (1)

Ramesh V
70 Points
							

note: dx/dt = v    dv/dx=a  and (dv/dx)*(dx/dt)=a

t=px2+qx

on differentiating wrt t , we have

1=2pxv+qv  .....(1)

on differentiating wrt x , we have

0=2pv+2px.dv/dx +q.dv/dx

0=2pv+2px.(a/v) +q.(a/v)

0=2pv2+2pxa +qa ....(2)

from (1) and (2) ..we have

2pv3+a=0

--

regards

Ramesh




10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details