Question icon
Grade 11Mechanics

1.A man of mass M having a bag of mass m slips from the roof of a tall building of height H and starts falling vertically. When at a height h from the ground he notices that the ground below him is pretty hard, but there is a pond at a horizontal distance x from the line of fall. In order to save himself he throws the bag horizontally (with respect to himself) in the direction opposite to the pond. Calculate the minimum horizontal velocity imparted to the bag so that the man lands in the water. If the man just succeeds to avoid the hard ground, where will the bag land?

Profile image of Nitish Mahato
16 Years agoGrade 11
Answers icon

1 Answer

Profile image of Ramesh V
16 Years ago

4875-2266_5850_untitled.JPG

let u,v be horizontal velocities of man and bag

balancing moments gives : Mu = mv

and h=1/2.g.t2   , x = ut

from all 3 eqns , we have hz. velocity of bag is  v = Mx /[m.(2h/g)1/2 ]

now tha bag will land at , y = vt

on solving all eqns we have

bag lands at : y = Mx/m

--

regards

Ramesh