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If the orbital velocity of moon is 1020m/s,find the time taken by the moon to complete one revolution around the eath.explain why this period is different from the period that is obseved from the earth which is 29.5day.

Deepesh kumar Lall , 14 Years ago

Grade 11

1 Answers

Devesh Lall

SOLUTION

Let the time taken by the moon to complete 1 revolution around the earth be T

' ' orbital velocity of the moon be v_o= 1020m/s = √[(r + h)/GM]

' ' radius of the earth be r = 6.4 X 10⁶m

' ' distance of moon from the earth be h = 3.4 X 10⁸ m

Since we know that the time period is given by :- T=2∏√[(r + h)³/GM] [Here G ---> Gravitational Constant and M --> Mass of earth]

Therefore now

T = 2∏√[(6.4 X 10⁶+ 3.4 X 10⁸)/6.67 X 10^-11 X 6 X 10³⁴] sec

On simplifying this you will get your answer.

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Mechanics> gravitation...

If the orbital velocity of moon is 1020m/s,find the time taken by the moon to complete one revolution around the eath.explain why this period is different from the period that is obseved from the earth which is 29.5day.

Deepesh kumar Lall , 14 Years ago

Devesh Lall

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