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A man of mass M stands at one end of a plank of length L which is at rest on a frictionless horizontal surface. The man walks to the other end of the plank. If mass of the plank is M/3, the distance that the man moves relative to ground is? Explain how pls...
The answer is L/4
initially the center of mass is at rest.
therefore the center of mass does not move in horizontal direction.
it is L/8 distance away from the end of the side of the man.
let x be the dispacement of the plank after the man walks to the other side.
then (L-x) will be the displacement of man.
let initially the center of mass be at origin i.e xi=0.
as we said earlier ,the center of mass will not move in horizontal direction therefore the center of mass remains stationary,
xi=xf
L/8=(m(L-x)+m/3(L/2-x))/(m+m/3) ( )
thus we get x=3L/4,
therefore the man moved L-x=L/4.
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