Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A block starts slipping from an incline and moves half a meter in half second, how much time will it require to cover next half meter?
As there is no mention of friction the block will undergo translational motion with constant accelearation of gsinβ (note βis the angle of inlclination of the inclined plane wit the ground).
Using,
S=ut+0.5at2
S=0.5at2 (initial velocity = 0)
0.5=0.5a(0.5)2
0.5=0.5(10sinβ)0.25 (g=10)
sinβ=2/5
Now as the half second is elapsed it requires the final velocity at the end of first half second is given by
v=u+at
v=gsinβt (u=0)
v=(10)(2/5)(1/2)
v=2m/s
But the above same velocity becomes the initial velocity for the second 1/2 second so now,
(1/2)=(2)t+0.5(10x2/5)t2
We Get,
A quadratic equation,
4t2 + 4t + -1 = 0
Solving we get
t=0.21 seconds
ANSWER:-Thus the block will require more 0.21 seconds to cover the more half of the distance.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !