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A gun is firing bullets with velocity Vo at the some angle with the horizontal by rotating through 90 degrees in the horizontal plane.The maximum area covered by bullets is?Please give solution for this.  Ans:)piVo ^4 /4g^2

Thank You!!!

P Krishna Chaitanya , 13 Years ago
Grade 11
anser 1 Answers
Chetan Mandayam Nayakar

Last Activity: 13 Years ago

range=Vo2sin(2*theta)/g, theta is angle of projection. Range is maximum when theta=45 degrees.

let the max. range be R

answer=(pi/4)R2

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