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the velocity time graph of the figure shown the motion of the wooden block of mass 1kg which is given an initial push at t=o along a horizontal table. a) the coefficient of friction b/w the block & table is 0.1 b)the coefficient of friction b/w the block & table is 0.2 c) if the table was half of its present roughness, the time taken by the bock to complete the journey is 4s d) if the table was half of its present roughness, the time taken by the bock to complete the journey is 8s. ans = (a) & (d) the velocity time graph of the figure shown the motion of the wooden block of mass 1kg which is given an initial push at t=o along a horizontal table. a) the coefficient of friction b/w the block & table is 0.1 b)the coefficient of friction b/w the block & table is 0.2 c) if the table was half of its present roughness, the time taken by the bock to complete the journey is 4s d) if the table was half of its present roughness, the time taken by the bock to complete the journey is 8s. ans = (a) & (d)
the velocity time graph of the figure shown the motion of the wooden block of mass 1kg which is given an initial push at t=o along a horizontal table.
a) the coefficient of friction b/w the block & table is 0.1
b)the coefficient of friction b/w the block & table is 0.2
c) if the table was half of its present roughness, the time taken by the bock to complete the journey is 4s
d) if the table was half of its present roughness, the time taken by the bock to complete the journey is 8s.
ans = (a) & (d)
Rate of change of velocity is acceleration. a=(4-0)/(4-0)(Total change of velocity/total time taken) a=1. As the system is isolated, the only force acting on it is the frictional force. So this acceleration is caused by frictional force. ma=kmg (where k is the coefficient of friction) a=kg k=a/g = 0.1. So option A.h As the coefficient of friction is reduced to half, the time taken will be twice. So option D.
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