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water rises in the height of 10 cm in capillry tube and mercury falls to a depth of 3.112 cm in the same capillary tube If the density of mercury is 13.6gm/cc and the angle of contact for mercury is 135 degree then ratio surface tension of water and mercury is

water rises in the height of 10 cm in capillry tube and mercury falls to a depth of 3.112 cm in the same capillary tube If the density of mercury is 13.6gm/cc and the angle of contact for mercury is 135 degree then ratio surface tension of water and mercury is 

Grade:12

1 Answers

askiitiansexpert soumyajit_iitkanpur
8 Points
11 years ago

Let a liquid of density ρ rise a height h in a capillary of raduis r, then we can write

hrρg = 2Tcosθ

where T is surface tension of that liquid and θ is angle of contact.

Let Tm and Tw be the surface tension of water and mercury.

Tm/Tw = [(3.112 * 13.6)/(10 * 1)] * [cosθw / cos(1350)]                (θw is the angle of contact of water)

         = 5.98*cosθw

 

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