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A spherical liquid drop of radius R is divided into eight equql droplets If surface tension is T then work done in the process will be

pallavi pradeep bhardwaj , 16 Years ago

Grade 12

2 Answers

askiitiansexpert soumyajit_iitkanpur

Volume of bigger drop = Total volume of 8 droplets

(4/3)*pi* R³ = 8 (4/3)* pi* r³

=> r = R/2

Change in surface area in this process = ds = 4* pi * [8*r² - R²] = 4* pi* R²

Hence work done = T.ds = T* 4*pi*R²

Last Activity: 16 Years ago

Soumyajit Mondal

V=8v

R³=n*r³

Work done =change in surface energy

ΔU=T * Δ Α

= T * 4 π ( n r² - R²)

= T* 4π n ( R² * n^ (-2/3) - R²)

= T 4π R² ( n^{1/3} - 1 )

Last Activity: 7 Years ago

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Mechanics> que-4...

A spherical liquid drop of radius R is divided into eight equql droplets If surface tension is T then work done in the process will be

pallavi pradeep bhardwaj , 16 Years ago

askiitiansexpert soumyajit_iitkanpur

Soumyajit Mondal

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