Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Work done in spliitting a drop of water of 1 mm radius into 10^6 droplets is

Work done in spliitting a drop of water of 1 mm radius into 10^6 droplets is

Grade:12

1 Answers

askiitiansexpert soumyajit_iitkanpur
8 Points
11 years ago

Let the radius of each droplet be r m and all the 10^6 droplets are identical.

Volume of bigger drop = Total volume of droplets

(4/3)* pi* (1* 10-3 )3 = 106 * (4/3)*pi * r3

=>  r = 10-5

Change in surface area = ds = 4* pi * [10* (10-5)2 - (10-3)2] m= 4* pi * 99* 10-6 m2

If the surface tension of water be T Nm-1 then work done W = T.ds J

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free