TO DERIVE EXPRESSION FOR RANGE WHEN THROWN DOWN THE PLANE WITH VELOCITY AT RIGHT ANGLE TO THE SLOPE WHICH IS? ? PLEASE DERIVE ?

Dear Pooja,

x range = vo² sin2 Θ /g
Where:
vo = launch velocity
Θ = launch angle; sin2 Θ = sin(2 * Θ)
g = acceleration of gravity,

In general ,

First we take the two components and find the timein which x component becomes zero and the 2*time*y component = Range.

Best Of luck

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