# Velocity-time graph of a particle moving in a straight line is as 10 shown in figure. Mass of the particle is 20 kg. What is the Work done by all the forces in KJ acting on the particle in time interval between t = 0 to t = 10 s?        (A)     5KJ        (B)     8KJ        (C)     6KJ        (D)     3KJPLS EXPLAIN!!!........my ans is c......but given ans is d..WHY???

Aman Bansal
592 Points
11 years ago

Dear Shivam,

The formula for Work done is:

W= F.d .Cos(theta)

where , F= Force

D= Displacement

Cos (thete ) = angle between the displacement and force applied.

And we know F= m.a ;m=mass and a = acceleration

Total work done = work done is 0-5sec + workdone in 5-10s

Thus you will get total work done = 3 KJ.

Best Of luck

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Thanks

Aman Bansal