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Velocity-time graph of a particle moving in a straight line is as 10 shown in figure. Mass of the particle is 20 kg. What is the Work done by all the forces in KJ acting on the particle in time interval between t = 0 to t = 10 s? (A) 5KJ (B) 8KJ (C) 6KJ (D) 3KJ PLS EXPLAIN!!!........my ans is c......but given ans is d..WHY???

 Velocity-time graph of a particle moving in a straight line is as 10 shown in figure. Mass of the particle is 20 kg. What is the Work done by all the forces in KJ acting on the particle in time interval between t = 0 to t = 10 s?


velocity-time-graph


 


        (A)     5KJ

        (B)     8KJ

        (C)     6KJ

        (D)     3KJ
PLS EXPLAIN!!!........my ans is c......but given ans is d..WHY???

Grade:9

1 Answers

Aman Bansal
592 Points
10 years ago

Dear Shivam,

The formula for Work done is:

 W= F.d .Cos(theta)

where , F= Force

D= Displacement 

Cos (thete ) = angle between the displacement and force applied.

And we know F= m.a ;m=mass and a = acceleration 

Total work done = work done is 0-5sec + workdone in 5-10s

Thus you will get total work done = 3 KJ.

Best Of luck

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