Helicapter mass 1000kg rises with verticle acceleration of 15ms^2 -passergersweigh 300kg-give magnitude,direction of the total helicapter on surrounding air?

Dear Siva,

(a) Force on the floor by the crew and passengers = 300 (15 +10) = 7500 N

(b) Force of the rotor on the surrounding air

=(1000 + 300)(15 + 10) = 32500N downward.

(c) From Newton s third law of motion, the air will have an equal and opposite reaction on the helicopter rotor blades = 32500 N upward.

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