# A particle of mass 1kg is moving along the line y=x+2 with speed 2m/s. The magnitude of angular momentum of particle about origin is??

Aman Bansal
592 Points
10 years ago

Dear Sai,

y = x + 2

r = x i, x + 2 j
v = sqrt(2) * (i + j)

angular momentum = r X mv = 1 * sqrt(2){(x i + (x + 2) j ) X (i + j) } = sqrt(2) (x k - x + 2k) = -2 sqrt(2) k

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Aman Bansal

Sakshi Bhavik
28 Points
4 years ago
Given data : Mass of the particles = 1 kg
Velocity of the particle = 2 m/s
Given Equation of motion of the particle : y = x+4 which indicates a straight line.
So , Angular momentum of the particle about the origin, L = r X p = mvr  sin θ where r is the perpendicular distance between the line and the origin.  Here, sin  θ = 1.
Thus , Angular momentum of the particle about the origin = mvr = 1 kg * 2m/s * 2m = 4 kg.m2/s