Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A wheel of moment of inertia 0.10 is rotating about a shaft at an angular speed of 160rev/min.A second wheel is set into rotation at 300 rev/min and is coupled to the same shaft so that both the wheels finally rotate with the common angular velocity of 200 rev/min.Find the moment of inertis of second wheel

A wheel of moment of inertia 0.10 is rotating about a shaft at an angular speed of 160rev/min.A second wheel is set into rotation at 300 rev/min and is coupled to the same shaft so that both the wheels finally rotate with the common angular velocity of 200 rev/min.Find the moment of inertis of second wheel

Grade:11

2 Answers

Swapnil Saxena
102 Points
9 years ago

For this purposeuse the law of conservation of angular momentum

I1(omega)1(Angular mom. of first wheel )+I2(omega)2 (Angular mom. of seconn d wheel )=(I1+I2)(omega)f (Angular mom. of combined system wheel )

(0.1)(320pi rad/min) + I2(600pi rad/min)=(0.1+I2)(400pi rad/min)

Solve the above equation and u will get the value of I2

Chetan Mandayam Nayakar
312 Points
9 years ago

I1 and I2 are moments of inertia

w1=160,w2=300,w3=200,

I1*w1 + I2*w2=(I1 + I2)*w3

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free

10th iCAT Scholarship Test Registration Form