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a machine gun of mass 12 kg fires bullets of mass 25g at the rate of 4 bullets/sec......with a velocity 500m/s...........what force must be applied to the gun to hold it in position.....??????????????????????PLS EXPLAIN!!!
First of all you should know that all Physics Qs are based on ideal conditions,so the momentum(linear) always remains conserved....
ie m1v1=m2v2
in this case
GUN BULLET
m1=12kg m2=25gm=>0.025kg=>(0.025*4)kg per sec
v1=x(let)m/s v2=500m/s
since momentum is conserved
12*x=0.025*4*500
x=(2.5*4*5)/12
x=4.16667m/s
F=change in momentum,so
12*4.1667-0="GIVES YOU THE CORRECT ANSWER!!"
PLZ APPROVE THE ANSWE
First of all you should know that all Physics Qs are based on ideal conditions,so the momentum(linear) always remains conserved.... ie m1v1=m2v2 in this case GUN BULLET m1=12kg m2=25gm=>0.025kg=>(0.025*4)kg per sec v1=x(let)m/s v2=500m/s since momentum is conserved 12*x=0.025*4*500 x=(2.5*4*5)/12 x=4.16667m/s F=change in momentum,so 12*4.1667-0="GIVES YOU THE CORRECT ANSWER!!"
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