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A cube of ice is floating in water.The fraction of its length that lie outside the water is(sp. gravity of ice=0.96)
a.0.04
b.0.4
c.0.96
d.none of these
The answer is 0.04.(a.)
Solution: Let the density of the ice = D , and the side = A then the mass of the ice cube = DA3 .
If it is floating in water then the weight must be balenced by the buyoant force (Vpg) where p is the mass of the water.
Then Mg= Vpg
= M= Vp
= DA3= Vp
Since D/p= 0.96 then 0.96A3=V
Since the base area of the cube = A2 , Then 0.96A3=A2l
Then 0.96 A = l where l is the length inside water . Then the fraction of length outside water is
(0.04 A)/A =0.04
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