A cube of ice is floating in water.The fraction of its length that lie outside the water is(sp. gravity of ice=0.96)

a.0.04

b.0.4

c.0.96

d.none of these

The answer is 0.04.(a.)

Solution:  Let the density of the ice  = D , and the side = A then the mass of the ice cube = DA³ .

If it is floating in water then the weight must be balenced by the buyoant force (Vpg) where p is the mass of the water.

Then Mg= Vpg

=  M= Vp

=  DA³= Vp

Since D/p= 0.96 then 0.96A³=V

Since the base area of the cube = A^{2 ,} Then 0.96A_³=A²l

Then 0.96 A = l where l is the length inside water . Then the fraction of length outside water is

(0.04 A)/A =0.04

Approved