Join now for JEE/NEET and also prepare for Boards Learn Science & Maths Concepts for JEE, NEET, CBSE @ Rs. 99! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A metallic sphere floats in immiscible mixture of water (density 103 kg/m3) and a liquid(density 8X103 kg/m3) such that its (2/3) part is in water (1/3) part in the liquid.The density of the metal is
a.5000/3 kg/m3
b.10000/3 kg/m3
c.5000 kg/m3
d.2000 kg/m3
for floation weight of the sphere should be equal to the net bouyant force
d=density of sphere ,d1=density of water,d2 =density of liquid
bouyant force f= weightof water displaced+weight of liquid displaced
f={(2/3)V*d1*g]+[(1/3)V*d2*g] = V*d*g
solving this we will get d=10000/3 kg/m3
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !