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A metallic sphere floats in immiscible mixture of water (density 103 kg/m3) and a liquid(density 8X103 kg/m3) such that its (2/3) part is in water (1/3) part in the liquid.The density of the metal is

a.5000/3 kg/m3

b.10000/3 kg/m3

c.5000 kg/m3

d.2000 kg/m3

Menka Malguri , 14 Years ago
Grade 12th Pass
anser 1 Answers
nitish kumar

for floation weight of the sphere should be equal to the net bouyant force

d=density of sphere ,d1=density of water,d2 =density of liquid

bouyant force f= weightof water displaced+weight of liquid displaced

f={(2/3)V*d1*g]+[(1/3)V*d2*g] = V*d*g

solving this we will get d=10000/3 kg/m3

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Last Activity: 14 Years ago
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