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a machine gun of mass 12 kg fires bullets at the rate of 4 bullets/sec......with a velocity 500m/s...........what force must be applied to the gun to hold it in position.....??????????????????????PLS EXPLAIN!!!
Hi Shivam,
Force is the rate of change of momentum (Newtons Second Law).
So F = 12*500*4 = 24000 kgms-2. = 24 kN.
Hence 24kN.
Hope it helps.
Regards,
Ashwin (IIT MadraS).
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