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a machine gun of mass 12 kg fires bullets at the rate of 4 bullets/sec......with a velocity 500m/s...........what force must be applied to the gun to hold it in position.....??????????????????????PLS EXPLAIN!!!

Shivam Bhagat , 13 Years ago
Grade 9
anser 1 Answers
Ashwin Muralidharan IIT Madras

Last Activity: 13 Years ago

Hi Shivam,

 

Force is the rate of change of momentum (Newtons Second Law).

So F = 12*500*4 = 24000 kgms-2. = 24 kN.

Hence 24kN.

 

Hope it helps.

 

Regards,

Ashwin (IIT MadraS).

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