Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Two blocks A and B of mass 1kg and 2 kg are connected together by means of a spring and are resting on a horizontal frictionless table. The blocks are then pulled apart so as to stretch the spring and then released. Find the ratio of their :
a) speed. b) momentum c) konetic energy at any instant.
Hi Arnab,
As the intial momentum of the system is zero (as they are relased from rest), and no external force acts on the system, the net momentum of the system should be 0 at any instant in time.
Let us say v1 and v2 are the speeds of the mass 1Kg and 2Kg respectively,
So 1*v1 = 2*v2
or v1/v2 = 2/1
And ratio of their momentum is 1.
Ratio of KE = 1*v1^2/2*v2^2 = 2.
Hope this helps.
Regards,
Ashwin (IIT Madras).
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !