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Since the trolley and man were initially at rest Their initial momenta is 0.
Once the man jumps and attains a velocity of 3m/s (with respect to ground) its momnetum is 60*3= 180kgm/s
Accor. to the law of conservation of momentum ,
0= 180+20v
v= 9m/s in the opposite direction.
Assuming that no deformation occur in the trolley ( deformation causes loss of energy) ,total energy that is produced by the man = 1/2(20*92+60*32 ) = 1/2((20*81)+(60*9)) = 1/2((1620)+(540)) = 1/2(2160)= 1080 J
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