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question:-
a particle of mass m is allowed to ocilate near the minimum of a vertical parabolic surface x^2=4ay,the angular frequency of smal ocilatons is given by:-
Dear Vishal,
Potential energy of the particle = mgy = mgx^2/(4a)As force = -dU/dxWe get force = -(mg/2a)*x = -kxgives k = mg/2aAngular frequency of oscillation omega = sqrt(k/m) = sqrt(g/2a)
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