Mechanics> Rigid Body Dynamics...
A Disc Of mass m, radius r is given an angular velocity w0(omega not). it is then placed on a horizontal rough surface with coeffecient of friction u(myu).
Find the time in which it stops.
1 Answers
areal mass density=m/(pi*r^2)=rho
mass of circular loop at radius a is rho*2*(pi)rdr=dm
Torque on the loop=(myu)*g*dm*a
Total torque=(myu)g*∫a dm (from a=0 to r)
angular deceleration=(torque/moment of inertia)
w0=(angular deceleration)*(time in which it stops)
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