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Ball A of mass m strikes a stationaty ball B of mass M and undergoes an elastic collision.After collision ball a has a speed one-third of its initial speed.The ratio of M/m is
a.1/4
b.1/2
c.2
d.4
Let the initial velocity of the body of mass m is V.
After collison , it became V/3.
Applying law of conservation of momentum
mV = mV/3 +MVo(Say)
(Assumption: the direction of the velocity doesnt changes after collison , otherwise not specified)
Then Vo = 2mV/3M----(1)
If the collison is Elastic, then energy remain conserved
=1/2(mV2) = 1/2(m(V/3)2+ MVo2)
=(mV2) = (m(V/3)2+ MVo2)
=8/9(mV2) = MVo2
Substituting value of Vo
= 8/9(mV2) = M(4m2V2/9M2)
= 8(m) = (4m2/M)
= M/m= (1/2)
Note: After collison Speed becomes 1/3 has an incomplete meaning. Direction of ball A should also be specified)
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