L-Shaped object consisting of two rods, each of length l and mass m, about an axis passing through the end-point of one of the rods and perpendicular to the plane of the LCalculate the moment of inertia

Hi Siddhant,

Lets first calculate the moment of inertia of the system about an axis passing through the common-point of one of the rods and perpendicular to the plane of the L

Then the moment of inertia = 2*(ML²/3) (where ML²/3 is the moment of inertia of one rod about an axis passing about one of its endpoints)

Using Parallel Axis Theorm

Moment of Inertia of the sytem about an axis passing through the end-point of one of the rods and perpendicular to the plane of the L 

= I + Md² (where d is the distance of the initail and final axis of rotation)

Here D= L (length of the rod)

then Moment of Inertia = 2(ML²)/3 + ((2M)L²) = 8(ML²)/3

Approved

Sorry for the calculation mistake, The moment of inertia = (2/3) ML² + (ML²) = 5ML²/3