A projectile is projected with speed 'u' at an angle of 60° with horizontal from the foot of an inclined plane.If the projectile hits the inclined plane horizontally , the range on inclined plane will be-(in terms of 'u' and 'g')
The projectile hits the inclined plane horizontally means at the instant of impact the projectile has only horizontal velocity.
or,it's vertical velocity is zero.
or,it is on it's highest point in the parabolic path.
or,it has gone only half the range for the given angle.
So, height of point of impac on inclined plane=height of projectile=u2Sin2θ/2g=3u2/8g
distance(length)of point of impact on inclined plane=1/2*range of projectile=u2Sinθ.Cosθ/g=√3u2/4g
So,range on inclined plane= [(length)2+(height)2]1/2 =√21u2/8g
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 9 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
