Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
anmol jain Grade: 11

A projectile is projected with speed 'u' at an angle of 60°  with horizontal from the foot of an inclined plane.If the projectile hits the inclined plane horizontally , the range on inclined plane will be-(in terms of 'u' and 'g')

8 years ago

Answers : (1)

askIITianexpert IITDelhi
8 Points

The projectile hits the inclined plane horizontally means at the instant of impact the projectile has only horizontal velocity.

or,it's vertical velocity is zero.

or,it is on it's highest point in the parabolic path.

or,it has gone only half the range for the given angle.

So, height of point of impac on inclined plane=height of projectile=u2Sin2θ/2g=3u2/8g

distance(length)of point of impact on inclined plane=1/2*range of projectile=u2Sinθ.Cosθ/g=√3u2/4g

So,range on inclined plane= [(length)2+(height)2]1/2 =√21u2/8g

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details