Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle mover along the parabolic path x=y2 + 2y + 2 in such a way that the y-component of velocity vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-
hi, parabolic path x=y2 + 2y + 2 differentiate w,r,t, t dx/dt = 2y dy/dt + 2 dy/dt Vx = 2 y Vy + 2 Vy Vx = 10y + 10 , again differentiating Ax = 10 dy/dt Ax = 50 m/sec^2 total Accl. = √ (Ax)^2 + (Ay)^2 Ay = 0 & Ax = 50 m/ sec^2 total accl. = 50 m/sec^2
hi,
parabolic path x=y2 + 2y + 2
differentiate w,r,t, t
dx/dt = 2y dy/dt + 2 dy/dt
Vx = 2 y Vy + 2 Vy
Vx = 10y + 10 , again differentiating
Ax = 10 dy/dt
Ax = 50 m/sec^2
total Accl. = √ (Ax)^2 + (Ay)^2
Ay = 0 & Ax = 50 m/ sec^2
total accl. = 50 m/sec^2
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -