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A particle mover along the parabolic path x=y 2 + 2y + 2 in such a way that the y-component of velocity vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-

A particle mover along the parabolic path x=y2 + 2y + 2 in such a way that the y-component of velocity vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-

Grade:11

1 Answers

Pratham Ashish
17 Points
12 years ago

hi,

parabolic path x=y2 + 2y + 2

differentiate w,r,t, t

     dx/dt = 2y dy/dt + 2 dy/dt

      Vx =  2 y Vy   + 2 Vy 

      Vx = 10y   + 10 , again differentiating

    Ax =  10 dy/dt 

   Ax =  50 m/sec^2 

 total Accl. = √ (Ax)^2 + (Ay)^2

            Ay = 0 & Ax = 50 m/ sec^2

   total accl. = 50 m/sec^2

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