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A particle mover along the parabolic path x=y2 + 2y + 2 in such a way that the y-component of velocity vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-
hi,
parabolic path x=y2 + 2y + 2
differentiate w,r,t, t
dx/dt = 2y dy/dt + 2 dy/dt
Vx = 2 y Vy + 2 Vy
Vx = 10y + 10 , again differentiating
Ax = 10 dy/dt
Ax = 50 m/sec^2
total Accl. = √ (Ax)^2 + (Ay)^2
Ay = 0 & Ax = 50 m/ sec^2
total accl. = 50 m/sec^2
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