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A person brings a mass if 1kg from infinity to a point A. Initially, the mass was at rest but it moves at a speed 3m/s as it reaches A. The work done by the person on the mass is -5.5 J. The gravitational potential at A is
a) -1 J/kg
b) -4.5 J/kg
c) -5.5 J/kg
d) -10 J/kg
Gravitiaonal Potential is the amount of energy needed to bring a unit mass from infinity to that point without causing any change in its velocity.
Thus, The work Done by the man on the particle = (Gravitational Potential at that point + Kinetic Energy of the particle)
-5.5 J -Kinetic Energy of the sytem = Gravitational Potential at that point.
-5.5 - 4.5 J(Kinetic Energy of the particle) = Gravitational Potential at that point.
-10 J/kg (Option (d) might be the answer)
Did not understand!!!
Gravitational potential + kinetic energy of particle =workdone
given to us workdone=-5.5 J
and kinetic energy=(m) * square(v) /2
so,here v=3
square(v)=9
mass=1
so kinetic energy=4.5
so, Gravitational potential=-5.5-4.5=-10 J/kg
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