If Ve is the escape velocity for earth when a projectile is fired from the surface of earth. Then the escape velocity if the same projectile is fired from its centre isa) root[3/2]Veb) 3/2Vec) root[2/3]Ved) 2/3Ve

The gravitational potential energy of a particle at the center of the earth is -(3/2)(GMm/R)

And that at the surface is (GMm/R)

Since Ve=(2* Gravitational Potential )^1/2. Then at Surface it is (2*GM/R)^1/2

At the Center it is  (2*3/2*GM/R)^1/2=(3*GM/R)^1/2

Then The ratios of the Escape velocity is Ve1 (at Center)/Ve (at Surface) =(3/2)^1/2

So the Correct Option is  (A)