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Three identical particles each of mass m are placed at the corners of an equilateral triangle of side l.The work done by external force to increase the side of triangle from l to 2l is
a) -3GM^2/2l
b) -3Gm^2/l
c) 3GM^2/2l
d) 3GM^2/l
The gravitational potential energy of the a pair of particles is -Gmm/l2
Since there exist three pairs (3 particles constitute three pairs) then the potential energie of system is -3(Gmm/l)
When the side of the cube is increased frm l to 2l then the potential energy of system is -3(Gmm/(2l))
Subtracting final Uf with initial Ui = 3(Gmm/(2l))
Note: If we are bringing the particles away frm each other then we have to supply energy against gravitation so it is definitely +. So no chance for option a,b
So clearly Option (c)
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