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The height from the surface of earth at which the gravitational potential energy of a ball of mass m is half of that at the centre of Earth is (where R is radius of earth) a) R/4 b) R/3 c) 3R/4 d) 4R/3

The height from the surface of earth at which the gravitational potential energy of a ball of mass m is half of that at the centre of Earth is (where R is radius of earth)


a) R/4


b) R/3


c) 3R/4


d) 4R/3

Grade:11

5 Answers

Swapnil Saxena
102 Points
11 years ago

The gravitational Potential energy of the particle at the center of the earth is (3/2)(GMm/R) . So the Height must be

(1/2)*(3/2)(GMm/R) (Potential Energy of the Particle at the center/2) =GMm/X (Potential Energy of the Particle at a height) = 4R/3. ---Ans

Arnab Mandal
18 Points
11 years ago

Answer is (b).

Arnab Mandal
18 Points
11 years ago

Answer is (b). Now Solve correctly and please post the detailed calculation.

Swapnil Saxena
102 Points
11 years ago

There is nothing wrong in the solution .Actually 4R/3 is the distance of the point from the center of the earth and R/3 from the surface.

Arnab Mandal
18 Points
11 years ago

Thank you. You were correct. Now please solve the "thermoprob" ones!!!!!!!

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