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The height from the surface of earth at which the gravitational potential energy of a ball of mass m is half of that at the centre of Earth is (where R is radius of earth)
a) R/4
b) R/3
c) 3R/4
d) 4R/3
5 Answers
Last Activity: 14 Years ago
The gravitational Potential energy of the particle at the center of the earth is (3/2)(GMm/R) . So the Height must be
(1/2)*(3/2)(GMm/R) (Potential Energy of the Particle at the center/2) =GMm/X (Potential Energy of the Particle at a height) = 4R/3. ---Ans
Last Activity: 14 Years ago
Answer is (b).
Last Activity: 14 Years ago
Answer is (b). Now Solve correctly and please post the detailed calculation.
Last Activity: 14 Years ago
There is nothing wrong in the solution .Actually 4R/3 is the distance of the point from the center of the earth and R/3 from the surface.
Last Activity: 14 Years ago
Thank you. You were correct. Now please solve the "thermoprob" ones!!!!!!!
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