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The height from the surface of earth at which the gravitational potential energy of a ball of mass m is half of that at the centre of Earth is (where R is radius of earth) a) R/4 b) R/3 c) 3R/4 d) 4R/3

The height from the surface of earth at which the gravitational potential energy of a ball of mass m is half of that at the centre of Earth is (where R is radius of earth)


a) R/4


b) R/3


c) 3R/4


d) 4R/3

Grade:11

5 Answers

Swapnil Saxena
102 Points
9 years ago

The gravitational Potential energy of the particle at the center of the earth is (3/2)(GMm/R) . So the Height must be

(1/2)*(3/2)(GMm/R) (Potential Energy of the Particle at the center/2) =GMm/X (Potential Energy of the Particle at a height) = 4R/3. ---Ans

Arnab Mandal
18 Points
9 years ago

Answer is (b).

Arnab Mandal
18 Points
9 years ago

Answer is (b). Now Solve correctly and please post the detailed calculation.

Swapnil Saxena
102 Points
9 years ago

There is nothing wrong in the solution .Actually 4R/3 is the distance of the point from the center of the earth and R/3 from the surface.

Arnab Mandal
18 Points
9 years ago

Thank you. You were correct. Now please solve the "thermoprob" ones!!!!!!!

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