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A body is weighed by a spring balance to be 1000N at the north pole. How much will it weight at the equator. Account for rotationof earth only.
The centrifugal forces will be acting on the particle at the equator but not on the poles (as the poles have 0 angular velocity).
As such the Weight will be reduced by mv2/R and becomes (mg - mv2/R) at the equator, where v is the linear velocity of the earth and R is the radius of the earth
But it remains mg at the poles.
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