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A satellite is seen every 6 hours over the equator. It is known that it rotates opposite to the direction of rotation of earth. Then the angular velocity (in radian per hour)of satellite about the centre of earth will be a) pi/2 b) pi/3 c) pi/4 d)pi/8

Arnab Mandal , 14 Years ago
Grade 11
anser 2 Answers
Swapnil Saxena

Let the angular velocity of the satellite with respect to the earth center is (Omega).

Angular Velocity of Earth surface at equator is 2pi/(24)=pi/12

Then relative velocity of the sattelite and the surface at  equator is (Omega + pi/12)

Time of Sight= 6 hrs

Then (Omega + pi/12)6 =2pi

==> (Omega + pi/12)   =pi/3

==> Omega = pi/4 --(ans)

Last Activity: 14 Years ago
Arnab Mandal

WHERE IS THE REPLY SWAPNIL SAXENA??

Last Activity: 14 Years ago
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