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A train of mass M is moving on a circular track or radius R with a constant speed V. The length of the train is half of the perimeter of the track.What will be the linear momentum of the train.
Please give a detailed solution.
A) Zero B)2Mv/pi C)MvR D)Mv
The answer posted by Ashwin (IIT Madras) is absolutely correct but with a silly mistake.
The ''R'' in the denominator gets cancelled out so it remains :
2 x (integral) M/pi x v cosx x dx {range from 0 to pi/2}
linear momnetum = 2Mv/pi
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