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Grade 11Mechanics

A mass m can rotate with angular velocity w1 on a smooth horizontal table being attached to a spring whose other end having passes through a hole in the table, supports another mass m.This other mass turns around as a conical pendulum with angular velocity w2. if l1 and l2 are the lengths of the string on and below table then

a)l1:l2=w1^2:w2^2

b)l1:l2=w2^2:w1^2

c)l1:l2=w1:w2

d0 none

Profile image of kritika agrawal
14 Years agoGrade 11
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1 Answer

Profile image of Ashwin Muralidharan IIT Madras
ApprovedApproved Tutor Answer14 Years ago

Hi Kritika,

 

Let "x" be the elongation in the spring.

 

So for the mass above the table

Kx = ml1w12

 

And for the mass below the table, let "Q" be the angle made by the spring with the vertical.

So kxsinQ = mrw22.

From the right triangle l2sinQ = r

So kxsinQ = m(l2sinQ)w22.

 

Hence l1:l2 = w22:w12.

 

Optoin (B)

 

Hope that helps.

 

Best Regards,

Ashwin (IIT Madras).