Ashwin Muralidharan IIT Madras
Last Activity: 13 Years ago
Hi Kritika,
Let "x" be the elongation in the spring.
So for the mass above the table
Kx = ml1w12
And for the mass below the table, let "Q" be the angle made by the spring with the vertical.
So kxsinQ = mrw22.
From the right triangle l2sinQ = r
So kxsinQ = m(l2sinQ)w22.
Hence l1:l2 = w22:w12.
Optoin (B)
Hope that helps.
Best Regards,
Ashwin (IIT Madras).