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12 RODS OF LENGTH L MAKE A CUBE. WHAT IS THE MOMENT OF INERTIA OF THE CUBE ABOUT ITS FACE DIAGONAL?
Let, the cube is made by 12 rods, we know that M.I. of each rod is ML2/2 ,
now let, talking about face of a cube at 2D i.e. a square ,
so its diagonal(or its length)= √2L
for square. MI is = M(√2L)2/2
= 2ML2/2
= ML2 (IT IS FOR 4 ROD) SO IT CAN BE :
=3ML2(FOR 12 RODS)
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