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Dear Akhil,
Work done≡∫F·ds (where F is force, and ds is infinitesimal displacement)
in circular motion F is always perpendicular to ds
therefore, F.ds≡zero. Therefore work done=zero
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Regards,
Askiitians Experts
Chetan Mandayam Nayakar
Work done by a conservative forces in a closed loop is zero . Since centrifugal and centripetal forces are conservative, work done in circular motion is zero .If any non-conservative force like friction is present work done is not zero
Conceptually,work done=force applied.displacement in the direction of force
When a particle moves in circular motion,two forces act on it,the tangential force and the centripetal force.
The centripetal force acts along the line joining the particle and the center of the circular path,but the particle is not diplaced in this direction due to the equal n opposite centrifugal applied on it and thus there is no displacement,hence no work done.
In case of tangential force,the direction of this force always keeps on changing as the direction of motion of the particle changes continuously.If we take any particular point on the circular path,the foce acts on the particle at that point in one direction and after taking a turn ,when the particle reaches the same point,the same force is applied but the displacement is zero,hence the work done is zero.
This can be applied for each n every point of the circular path n hence the work done at each n every point of the circular path is zero.
Hi Akhil,
We don't take it to be zero.
If you see W = (F vector)dot(Displacement vector).
At any instant in time, F is towards the centre, and the displacement is along the tangent to the circle.
And hence these two vectors are perpendicular. (So sot roduct is zero).
And hence W = 0.
Best Regards,
Ashwin (IIT Madras).
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