a particle is moving in a circle of radius R in such a way that at any instant the norml &tangential components of its accelkeration are equal if its speed at t=0 is v the time taken to complete the first revolution?
ω2r=αr, which implies that α=ω2,u=rω,where u is tangential velocity
u=v+αt,ω=(v+(alpha*t))/R,
ω=(v+ω2t)/R,now we have obtained a quadratic equation in omega.
Solve it to obtain omega as a function of 't'
from v=R*(omega),find v as a function of t,in addition,alpha=(omega)^2
u=v+(alpha*t)=v+ω2t
Solve it to obtain omega as a function of 't'
∫(v+αt)*dt (from t=0 to t=T)=2pi*R
you will get an equation in ' t',solve it to obtain the answer 'T'
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 9 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
