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on inclined wedge a body is inclined on it having mass m 60N force is acting from the direction of mgsin@ and another force 60N from direction of mgcos@ what is the aaceleration of body if @=angle
It should be gsin@ and from my calculation it shoul be @= 45 AND acc. = 10/root2
mgsin@ = 60
mgcos@ = 60
net force = sqr. root of (602 + 602) = (sqr. root of 2) * 60
you will get acceleration by dividing the value of net force by the mass of the body
final ans :- 10 m/s2
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