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The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct? The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?
The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?
Acceleration due to gravity at a depth 'd' from earth surface is :
correct answer=gh = g(1- 2h ) R
Dear student,Please find the solution to your problem below. The acc. due to gravity at height h above earth, gh = g(1 – 2h/R) [considering h The acc. due to gravity at a depth d below the ground level, gd = g(1 – d/R)Now equating, gd = ghHence, d = 2h Hope it helps.Thanks and regards,Kushagra
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