Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?

The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?

Grade:12

4 Answers

dev bhatnagar
8 Points
12 years ago

 

Acceleration due to gravity at a depth 'd' from earth surface is :


gd = g(1-   d  )
 R





Acceleration due to gravity at height 'h' from earth surface is :
h is very much smaller than R
gh = g(1-   2h  )
 R





gh = gd
By solving it , d=2h

Omkar ajit Darekar
33 Points
12 years ago
correct answer=gh = g(1- 2h ) R
Omkar ajit Darekar
33 Points
12 years ago

gh = g(1-   2h  )
 R
=correct answer

Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the solution to your problem below.
 
The acc. due to gravity at height h above earth, gh = g(1 – 2h/R)     [considering h
The acc. due to gravity at a depth d below the ground level, gd = g(1 – d/R)
Now equating, gd = gh
Hence, d = 2h
 
Hope it helps.
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free