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The change in the value of g at a height h above the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?

12 years ago

Acceleration due to gravity at a depth 'd' from earth surface is :

 gd = g(1- d ) R

Acceleration due to gravity at height 'h' from earth surface is :
h is very much smaller than R
 gh = g(1- 2h ) R

gh = gd
By solving it , d=2h Kushagra Madhukar
one year ago
Dear student,

The acc. due to gravity at height h above earth, gh = g(1 – 2h/R)     [considering h
The acc. due to gravity at a depth d below the ground level, gd = g(1 – d/R)
Now equating, gd = gh
Hence, d = 2h

Hope it helps.
Thanks and regards,
Kushagra