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Grade: Upto college level
        Two cars of unequal masses use similar tyres.If they are moving with at the same initial speed,the minimum stopping distance(a)is smaller for the heavier car(b)is smaller for the lighter car(c)is same for both cars(d)depends on the volume of the car
10 years ago

Answers : (1)

pratham ashish
9 Points
Ans to ur Qn is(c)the distance is same for both cars

See how :

        the friction force is mue*m1*g           (mue = friction coeff.)
 for other
         the friction force is mue*m2*g          (mue is same for both as both have same type                  
                                                                      of tyres)    
 but retardetion due to friction 

                 for I car = mue*m1*g/m1
                           = mue*g

                 for II car = mue*m2*g/m2
                            = mue*g

               retardation is same for both , so time taken in stopping will also be same

                   As  s = ut+ (at^2)/2

HAVE NICE LUCK               

10 years ago
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