Grade Upto college levelMechanics
1 Answer
pratham ashish
Hi,
Ans to ur Qn is(c)the distance is same for both cars
See how :
the friction force is mue*m1*g (mue = friction coeff.)
for other
the friction force is mue*m2*g (mue is same for both as both have same type
of tyres)
but retardetion due to friction
for I car = mue*m1*g/m1
= mue*g
for II car = mue*m2*g/m2
= mue*g
retardation is same for both , so time taken in stopping will also be same
As s = ut+ (at^2)/2
HAVE NICE LUCK
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