MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: Upto college level
        Two cars of unequal masses use similar tyres.If they are moving with at the same initial speed,the minimum stopping distance(a)is smaller for the heavier car(b)is smaller for the lighter car(c)is same for both cars(d)depends on the volume of the car
10 years ago

Answers : (1)

pratham ashish
9 Points
							Hi, 
 
Ans to ur Qn is(c)the distance is same for both cars

See how :

        the friction force is mue*m1*g           (mue = friction coeff.)
 for other
   
         the friction force is mue*m2*g          (mue is same for both as both have same type                  
                                                                      of tyres)    
 but retardetion due to friction 

                 for I car = mue*m1*g/m1
                           = mue*g

                 for II car = mue*m2*g/m2
                            = mue*g

               retardation is same for both , so time taken in stopping will also be same

                   As  s = ut+ (at^2)/2


HAVE NICE LUCK               

         
						
10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details